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201833451113 = 7148511941509
BaseRepresentation
bin1011101111111000110…
…1100000111001101001
3201021222010020122121012
42323332031200321221
511301323330413423
6232415423153305
720403423012350
oct2737615407151
9637863218535
10201833451113
11786627a3158
1233149745835
1316057121ca8
149aa97c4997
1553b43d9078
hex2efe360e69

201833451113 has 8 divisors (see below), whose sum is σ = 230682452160. Its totient is φ = 172988362800.

The previous prime is 201833451011. The next prime is 201833451121. The reversal of 201833451113 is 311154338102.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 201833451113 - 236 = 133113974377 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 201833451113.

It is not an unprimeable number, because it can be changed into a prime (201833454113) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 866798 + ... + 1074711.

It is an arithmetic number, because the mean of its divisors is an integer number (28835306520).

Almost surely, 2201833451113 is an apocalyptic number.

It is an amenable number.

201833451113 is a deficient number, since it is larger than the sum of its proper divisors (28849001047).

201833451113 is a wasteful number, since it uses less digits than its factorization.

201833451113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1956367.

The product of its (nonzero) digits is 8640, while the sum is 32.

Adding to 201833451113 its reverse (311154338102), we get a palindrome (512987789215).

The spelling of 201833451113 in words is "two hundred one billion, eight hundred thirty-three million, four hundred fifty-one thousand, one hundred thirteen".

Divisors: 1 7 14851 103957 1941509 13590563 28833350159 201833451113