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2020121112193 = 12791579453567
BaseRepresentation
bin11101011001011000100…
…110011110111010000001
321011010021201021020220121
4131121120212132322001
5231044202001042233
64144010354140241
7265643325064522
oct35313046367201
97133251236817
102020121112193
11709801781228
1228761a581681
1311865c065212
146dabaca0849
15378346bd92d
hex1d65899ee81

2020121112193 has 4 divisors (see below), whose sum is σ = 2021700567040. Its totient is φ = 2018541657348.

The previous prime is 2020121112127. The next prime is 2020121112287. The reversal of 2020121112193 is 3912111210202.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2020121112193 - 217 = 2020120981121 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2020121113193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 789725505 + ... + 789728062.

It is an arithmetic number, because the mean of its divisors is an integer number (505425141760).

Almost surely, 22020121112193 is an apocalyptic number.

It is an amenable number.

2020121112193 is a deficient number, since it is larger than the sum of its proper divisors (1579454847).

2020121112193 is a wasteful number, since it uses less digits than its factorization.

2020121112193 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1579454846.

The product of its (nonzero) digits is 432, while the sum is 25.

Adding to 2020121112193 its reverse (3912111210202), we get a palindrome (5932232322395).

The spelling of 2020121112193 in words is "two trillion, twenty billion, one hundred twenty-one million, one hundred twelve thousand, one hundred ninety-three".

Divisors: 1 1279 1579453567 2020121112193