Base | Representation |
---|---|
bin | 101101111011101011100011… |
… | …110001001011111101000001 |
3 | 222111021021200010110120210021 |
4 | 231323223203301023331001 |
5 | 202434241231124401423 |
6 | 1553351345044533441 |
7 | 60356660135431633 |
oct | 5573534361137501 |
9 | 874237603416707 |
10 | 202013313122113 |
11 | 59405401865899 |
12 | 1a7a76499b1281 |
13 | 8894a09a386ac |
14 | 37c56d466aa53 |
15 | 1854c6ac2095d |
hex | b7bae3c4bf41 |
202013313122113 has 8 divisors (see below), whose sum is σ = 202743137969600. Its totient is φ = 201283492123440.
The previous prime is 202013313122107. The next prime is 202013313122167. The reversal of 202013313122113 is 311221313310202.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 202013313122113 - 213 = 202013313113921 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (202013313122183) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 143069038 + ... + 144474136.
It is an arithmetic number, because the mean of its divisors is an integer number (25342892246200).
Almost surely, 2202013313122113 is an apocalyptic number.
It is an amenable number.
202013313122113 is a deficient number, since it is larger than the sum of its proper divisors (729824847487).
202013313122113 is a wasteful number, since it uses less digits than its factorization.
202013313122113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1924407.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 202013313122113 its reverse (311221313310202), we get a palindrome (513234626432315).
The spelling of 202013313122113 in words is "two hundred two trillion, thirteen billion, three hundred thirteen million, one hundred twenty-two thousand, one hundred thirteen".
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