Base | Representation |
---|---|
bin | 101101111011101100100100… |
… | …100011011000001010001101 |
3 | 222111021101110212122202221112 |
4 | 231323230210203120022031 |
5 | 202434300442401134013 |
6 | 1553352044552541405 |
7 | 60360026104061510 |
oct | 5573544443301215 |
9 | 874241425582845 |
10 | 202014400021133 |
11 | 5940590a342147 |
12 | 1a7a78b19b1865 |
13 | 8894b50c801cb |
14 | 37c5798b58d77 |
15 | 1854cd1369ba8 |
hex | b7bb248d828d |
202014400021133 has 16 divisors (see below), whose sum is σ = 231530135040000. Its totient is φ = 172662854731632.
The previous prime is 202014400021111. The next prime is 202014400021193. The reversal of 202014400021133 is 331120004410202.
202014400021133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 202014400021133 - 234 = 201997220151949 is a prime.
It is a super-3 number, since 3×2020144000211333 (a number of 44 digits) contains 333 as substring.
It is a Duffinian number.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 202014400021099 and 202014400021108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (202014400021193) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 41148908 + ... + 45795866.
It is an arithmetic number, because the mean of its divisors is an integer number (14470633440000).
Almost surely, 2202014400021133 is an apocalyptic number.
It is an amenable number.
202014400021133 is a deficient number, since it is larger than the sum of its proper divisors (29515735018867).
202014400021133 is a wasteful number, since it uses less digits than its factorization.
202014400021133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4664624.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 202014400021133 its reverse (331120004410202), we get a palindrome (533134404431335).
The spelling of 202014400021133 in words is "two hundred two trillion, fourteen billion, four hundred million, twenty-one thousand, one hundred thirty-three".
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