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20202012202011 = 36734004067337
BaseRepresentation
bin1001001011111101001011…
…10000101101010000011011
32122112021220222001122101120
410211332211300231100123
510121442210110431021
6110544402024420323
74153355460301023
oct445764560552033
978467828048346
1020202012202011
11648969724a402
1223233510176a3
13b37070460193
144dbad5692a83
15250779ccd2c6
hex125fa5c2d41b

20202012202011 has 4 divisors (see below), whose sum is σ = 26936016269352. Its totient is φ = 13468008134672.

The previous prime is 20202012202003. The next prime is 20202012202027. The reversal of 20202012202011 is 11020221020202.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20202012202011 - 23 = 20202012202003 is a prime.

It is not an unprimeable number, because it can be changed into a prime (20202012202111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3367002033666 + ... + 3367002033671.

It is an arithmetic number, because the mean of its divisors is an integer number (6734004067338).

Almost surely, 220202012202011 is an apocalyptic number.

20202012202011 is a deficient number, since it is larger than the sum of its proper divisors (6734004067341).

20202012202011 is an equidigital number, since it uses as much as digits as its factorization.

20202012202011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6734004067340.

The product of its (nonzero) digits is 64, while the sum is 15.

Adding to 20202012202011 its reverse (11020221020202), we get a palindrome (31222233222213).

The spelling of 20202012202011 in words is "twenty trillion, two hundred two billion, twelve million, two hundred two thousand, eleven".

Divisors: 1 3 6734004067337 20202012202011