Search a number
-
+
20202100000113 = 36734033333371
BaseRepresentation
bin1001001011111101010101…
…11111101000010101110001
32122112022011002021020202010
410211332222333220111301
510121442400100000423
6110544414442313133
74153360604463123
oct445765277502561
978468132236663
1020202100000113
116489731867419
1223233764b87a9
13b370856c0b15
144dbb031c9213
15250782872693
hex125faafe8571

20202100000113 has 4 divisors (see below), whose sum is σ = 26936133333488. Its totient is φ = 13468066666740.

The previous prime is 20202100000111. The next prime is 20202100000123. The reversal of 20202100000113 is 31100000120202.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 20202100000113 - 21 = 20202100000111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20202100000111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3367016666683 + ... + 3367016666688.

It is an arithmetic number, because the mean of its divisors is an integer number (6734033333372).

Almost surely, 220202100000113 is an apocalyptic number.

It is an amenable number.

20202100000113 is a deficient number, since it is larger than the sum of its proper divisors (6734033333375).

20202100000113 is an equidigital number, since it uses as much as digits as its factorization.

20202100000113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6734033333374.

The product of its (nonzero) digits is 24, while the sum is 12.

Adding to 20202100000113 its reverse (31100000120202), we get a palindrome (51302100120315).

The spelling of 20202100000113 in words is "twenty trillion, two hundred two billion, one hundred million, one hundred thirteen", and thus it is an aban number.

Divisors: 1 3 6734033333371 20202100000113