Base | Representation |
---|---|
bin | 101101111100000100101000… |
… | …010001110100111101001011 |
3 | 222111100212011011201012011202 |
4 | 231330010220101310331023 |
5 | 202440211343434130011 |
6 | 1553412000145014415 |
7 | 60361632206104463 |
oct | 5574045021647513 |
9 | 874325134635152 |
10 | 202040232333131 |
11 | 59415865a79525 |
12 | 1a7b090102440b |
13 | 8897409a70a1a |
14 | 37c6b2987cba3 |
15 | 18557e414823b |
hex | b7c128474f4b |
202040232333131 has 8 divisors (see below), whose sum is σ = 202549136511600. Its totient is φ = 201531566134912.
The previous prime is 202040232333083. The next prime is 202040232333139. The reversal of 202040232333131 is 131333232040202.
It is a happy number.
202040232333131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 202040232333131 - 242 = 197642185822027 is a prime.
It is a super-2 number, since 2×2020402323331312 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 202040232333094 and 202040232333103.
It is not an unprimeable number, because it can be changed into a prime (202040232333139) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 57794906 + ... + 61190943.
It is an arithmetic number, because the mean of its divisors is an integer number (25318642063950).
Almost surely, 2202040232333131 is an apocalyptic number.
202040232333131 is a deficient number, since it is larger than the sum of its proper divisors (508904178469).
202040232333131 is a wasteful number, since it uses less digits than its factorization.
202040232333131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 118990125.
The product of its (nonzero) digits is 15552, while the sum is 29.
Adding to 202040232333131 its reverse (131333232040202), we get a palindrome (333373464373333).
The spelling of 202040232333131 in words is "two hundred two trillion, forty billion, two hundred thirty-two million, three hundred thirty-three thousand, one hundred thirty-one".
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