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202043121231 = 379621101011
BaseRepresentation
bin1011110000101010110…
…1010101111001001111
3201022111201202222221010
42330022231111321033
511302241014334411
6232452313140303
720411550123450
oct2741255257117
9638451688833
10202043121231
1178760090446
12331a79ba693
131608b6b3953
149ac95a3127
1553c7a037a6
hex2f0ab55e4f

202043121231 has 8 divisors (see below), whose sum is σ = 307875232384. Its totient is φ = 115453212120.

The previous prime is 202043121221. The next prime is 202043121233. The reversal of 202043121231 is 132121340202.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 202043121231 - 213 = 202043113039 is a prime.

It is a super-2 number, since 2×2020431212312 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (21), and also a Moran number because the ratio is a prime number: 9621101011 = 202043121231 / (2 + 0 + 2 + 0 + 4 + 3 + 1 + 2 + 1 + 2 + 3 + 1).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 202043121198 and 202043121207.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (202043121233) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4810550485 + ... + 4810550526.

It is an arithmetic number, because the mean of its divisors is an integer number (38484404048).

Almost surely, 2202043121231 is an apocalyptic number.

202043121231 is a gapful number since it is divisible by the number (21) formed by its first and last digit.

202043121231 is a deficient number, since it is larger than the sum of its proper divisors (105832111153).

202043121231 is an equidigital number, since it uses as much as digits as its factorization.

202043121231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9621101021.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 202043121231 its reverse (132121340202), we get a palindrome (334164461433).

The spelling of 202043121231 in words is "two hundred two billion, forty-three million, one hundred twenty-one thousand, two hundred thirty-one".

Divisors: 1 3 7 21 9621101011 28863303033 67347707077 202043121231