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202113004215 = 3513474200281
BaseRepresentation
bin1011110000111011011…
…1111011001010110111
3201022200121021102100210
42330032313323022313
511302411412113330
6232503251040503
720413356122103
oct2741667731267
9638617242323
10202113004215
1178796581581
12332072a0133
13160a0011125
149ad4994903
1553cdc098b0
hex2f0edfb2b7

202113004215 has 8 divisors (see below), whose sum is σ = 323380806768. Its totient is φ = 107793602240.

The previous prime is 202113004187. The next prime is 202113004217. The reversal of 202113004215 is 512400311202.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 202113004215 - 26 = 202113004151 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 202113004191 and 202113004200.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (202113004217) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6737100126 + ... + 6737100155.

It is an arithmetic number, because the mean of its divisors is an integer number (40422600846).

Almost surely, 2202113004215 is an apocalyptic number.

202113004215 is a deficient number, since it is larger than the sum of its proper divisors (121267802553).

202113004215 is a wasteful number, since it uses less digits than its factorization.

202113004215 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13474200289.

The product of its (nonzero) digits is 480, while the sum is 21.

Adding to 202113004215 its reverse (512400311202), we get a palindrome (714513315417).

The spelling of 202113004215 in words is "two hundred two billion, one hundred thirteen million, four thousand, two hundred fifteen".

Divisors: 1 3 5 15 13474200281 40422600843 67371001405 202113004215