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202113413100 = 22325217234991151
BaseRepresentation
bin1011110000111011100…
…1011110111111101100
3201022200122001012020200
42330032321132333230
511302412013204400
6232503303513500
720413362444144
oct2741671367754
9638618035220
10202113413100
11787968307a5
1233207458890
13160a0125281
149ad4a5d924
1553cdc8ab00
hex2f0ee5efec

202113413100 has 432 divisors, whose sum is σ = 701955072000. Its totient is φ = 48381696000.

The previous prime is 202113413087. The next prime is 202113413107. The reversal of 202113413100 is 1314311202.

202113413100 is a `hidden beast` number, since 2 + 0 + 2 + 11 + 341 + 310 + 0 = 666.

It is a super-2 number, since 2×2021134131002 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is not an unprimeable number, because it can be changed into a prime (202113413107) by changing a digit.

It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 175597525 + ... + 175598675.

It is an arithmetic number, because the mean of its divisors is an integer number (1624896000).

Almost surely, 2202113413100 is an apocalyptic number.

202113413100 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 202113413100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (350977536000).

202113413100 is an abundant number, since it is smaller than the sum of its proper divisors (499841658900).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

202113413100 is a wasteful number, since it uses less digits than its factorization.

202113413100 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1710 (or 1700 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 202113413100 its reverse (1314311202), we get a palindrome (203427724302).

The spelling of 202113413100 in words is "two hundred two billion, one hundred thirteen million, four hundred thirteen thousand, one hundred".