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2021141002143 = 36531031720777
BaseRepresentation
bin11101011010010101011…
…001000011011110011111
321011012220210101000220110
4131122111121003132133
5231103244044032033
64144255510021103
7266010521025564
oct35322531033637
97135823330813
102021141002143
1170a18544a68a
12287864047793
131187924476b3
146db7650886b
1537893ecd363
hex1d69564379f

2021141002143 has 8 divisors (see below), whose sum is σ = 2698981555248. Its totient is φ = 1345363891904.

The previous prime is 2021141002129. The next prime is 2021141002147. The reversal of 2021141002143 is 3412001411202.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2021141002143 - 210 = 2021141001119 is a prime.

It is a super-2 number, since 2×20211410021432 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2021141002147) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 515858430 + ... + 515862347.

It is an arithmetic number, because the mean of its divisors is an integer number (337372694406).

Almost surely, 22021141002143 is an apocalyptic number.

2021141002143 is a deficient number, since it is larger than the sum of its proper divisors (677840553105).

2021141002143 is a wasteful number, since it uses less digits than its factorization.

2021141002143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1031721433.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 2021141002143 its reverse (3412001411202), we get a palindrome (5433142413345).

The spelling of 2021141002143 in words is "two trillion, twenty-one billion, one hundred forty-one million, two thousand, one hundred forty-three".

Divisors: 1 3 653 1959 1031720777 3095162331 673713667381 2021141002143