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20213332103 = 1491013133919
BaseRepresentation
bin10010110100110011…
…101111100010000111
31221011200221122212202
4102310303233202013
5312344103111403
613141425505115
71313622326246
oct226463574207
957150848782
1020213332103
118632998648
123b014a219b
131ba194c353
14d9a77895d
157d485a688
hex4b4cef887

20213332103 has 8 divisors (see below), whose sum is σ = 20369232000. Its totient is φ = 20057702368.

The previous prime is 20213332063. The next prime is 20213332109. The reversal of 20213332103 is 30123331202.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 20213332103 - 210 = 20213331079 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20213332109) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 83978 + ... + 217896.

It is an arithmetic number, because the mean of its divisors is an integer number (2546154000).

Almost surely, 220213332103 is an apocalyptic number.

20213332103 is a deficient number, since it is larger than the sum of its proper divisors (155899897).

20213332103 is a wasteful number, since it uses less digits than its factorization.

20213332103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 135081.

The product of its (nonzero) digits is 648, while the sum is 20.

Adding to 20213332103 its reverse (30123331202), we get a palindrome (50336663305).

Subtracting 20213332103 from its reverse (30123331202), we obtain a palindrome (9909999099).

The spelling of 20213332103 in words is "twenty billion, two hundred thirteen million, three hundred thirty-two thousand, one hundred three".

Divisors: 1 149 1013 133919 150937 19953931 135659947 20213332103