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202144124113 = 1910639164427
BaseRepresentation
bin1011110001000010111…
…0101000110011010001
3201022202202211110211121
42330100232220303101
511302442343432423
6232510322042241
720414214463501
oct2742056506321
9638682743747
10202144124113
11788020a73a8
12332157a9381
13160a65b8a79
149ad8b75a01
1553d180545d
hex2f10ba8cd1

202144124113 has 4 divisors (see below), whose sum is σ = 212783288560. Its totient is φ = 191504959668.

The previous prime is 202144124111. The next prime is 202144124153. The reversal of 202144124113 is 311421441202.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 202144124113 - 21 = 202144124111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (202144124111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5319582195 + ... + 5319582232.

It is an arithmetic number, because the mean of its divisors is an integer number (53195822140).

Almost surely, 2202144124113 is an apocalyptic number.

It is an amenable number.

202144124113 is a deficient number, since it is larger than the sum of its proper divisors (10639164447).

202144124113 is a wasteful number, since it uses less digits than its factorization.

202144124113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10639164446.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 202144124113 its reverse (311421441202), we get a palindrome (513565565315).

The spelling of 202144124113 in words is "two hundred two billion, one hundred forty-four million, one hundred twenty-four thousand, one hundred thirteen".

Divisors: 1 19 10639164427 202144124113