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20220000041 = 107188971963
BaseRepresentation
bin10010110101001101…
…001011011100101001
31221012011111102120102
4102311031023130221
5312402310000131
613142224435145
71314033110303
oct226515133451
957164442512
1020220000041
11863673233a
123b03778ab5
131ba3145387
14d9b5d2973
157d52261cb
hex4b534b729

20220000041 has 4 divisors (see below), whose sum is σ = 20408972112. Its totient is φ = 20031027972.

The previous prime is 20219999999. The next prime is 20220000079. The reversal of 20220000041 is 14000002202.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20220000041 - 214 = 20219983657 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 20219999977 and 20220000031.

It is not an unprimeable number, because it can be changed into a prime (20220000841) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 94485875 + ... + 94486088.

It is an arithmetic number, because the mean of its divisors is an integer number (5102243028).

Almost surely, 220220000041 is an apocalyptic number.

It is an amenable number.

20220000041 is a deficient number, since it is larger than the sum of its proper divisors (188972071).

20220000041 is a wasteful number, since it uses less digits than its factorization.

20220000041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 188972070.

The product of its (nonzero) digits is 32, while the sum is 11.

Adding to 20220000041 its reverse (14000002202), we get a palindrome (34220002243).

The spelling of 20220000041 in words is "twenty billion, two hundred twenty million, forty-one", and thus it is an aban number.

Divisors: 1 107 188971963 20220000041