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20221000113 = 36740333371
BaseRepresentation
bin10010110101010000…
…111111100110110001
31221012020101020102010
4102311100333212301
5312403034000423
613142302113133
71314044444046
oct226520774661
957166336363
1020221000113
118637255746
123b03b7b7a9
131ba3405632
14d9b7b31cd
157d5372693
hex4b543f9b1

20221000113 has 4 divisors (see below), whose sum is σ = 26961333488. Its totient is φ = 13480666740.

The previous prime is 20221000109. The next prime is 20221000141. The reversal of 20221000113 is 31100012202.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 20221000113 - 22 = 20221000109 is a prime.

It is a super-4 number, since 4×202210001134 (a number of 42 digits) contains 4444 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20221000153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3370166683 + ... + 3370166688.

It is an arithmetic number, because the mean of its divisors is an integer number (6740333372).

Almost surely, 220221000113 is an apocalyptic number.

It is an amenable number.

20221000113 is a deficient number, since it is larger than the sum of its proper divisors (6740333375).

20221000113 is an equidigital number, since it uses as much as digits as its factorization.

20221000113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6740333374.

The product of its (nonzero) digits is 24, while the sum is 12.

Adding to 20221000113 its reverse (31100012202), we get a palindrome (51321012315).

The spelling of 20221000113 in words is "twenty billion, two hundred twenty-one million, one hundred thirteen", and thus it is an aban number.

Divisors: 1 3 6740333371 20221000113