Base | Representation |
---|---|
bin | 101101111110100010101111… |
… | …111000000011000100011001 |
3 | 222111222002101100020010211220 |
4 | 231332202233320003010121 |
5 | 203001002100304013423 |
6 | 1554021555135042253 |
7 | 60410122402011003 |
oct | 5576425770030431 |
9 | 874862340203756 |
10 | 202210011001113 |
11 | 59480869673675 |
12 | 1a8197a3670389 |
13 | 88aa425bb1ccb |
14 | 37d1033d7d373 |
15 | 1859e2e3239e3 |
hex | b7e8afe03119 |
202210011001113 has 16 divisors (see below), whose sum is σ = 274262940203136. Its totient is φ = 132485582759040.
The previous prime is 202210011001067. The next prime is 202210011001121. The reversal of 202210011001113 is 311100110012202.
It is not a de Polignac number, because 202210011001113 - 228 = 202209742565657 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 202210011001092 and 202210011001101.
It is not an unprimeable number, because it can be changed into a prime (202210011001123) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 462888445 + ... + 463325082.
It is an arithmetic number, because the mean of its divisors is an integer number (17141433762696).
Almost surely, 2202210011001113 is an apocalyptic number.
It is an amenable number.
202210011001113 is a deficient number, since it is larger than the sum of its proper divisors (72052929202023).
202210011001113 is a wasteful number, since it uses less digits than its factorization.
202210011001113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 926214784.
The product of its (nonzero) digits is 24, while the sum is 15.
Adding to 202210011001113 its reverse (311100110012202), we get a palindrome (513310121013315).
The spelling of 202210011001113 in words is "two hundred two trillion, two hundred ten billion, eleven million, one thousand, one hundred thirteen".
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