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2022102012113 = 3316109069523
BaseRepresentation
bin11101011011001110101…
…011000001000011010001
321011022101202200101202022
4131123032223001003101
5231112231103341423
64144535115501225
7266043400336121
oct35331653010321
97138352611668
102022102012113
1170a6289626a7
12287a91a57815
131188b6582951
146dc27dc6c81
15378ed55bdc8
hex1d6ceac10d1

2022102012113 has 4 divisors (see below), whose sum is σ = 2028211081968. Its totient is φ = 2015992942260.

The previous prime is 2022102012107. The next prime is 2022102012169. The reversal of 2022102012113 is 3112102012202.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2022102012113 - 24 = 2022102012097 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2022102012091 and 2022102012100.

It is not an unprimeable number, because it can be changed into a prime (2022102012013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3054534431 + ... + 3054535092.

It is an arithmetic number, because the mean of its divisors is an integer number (507052770492).

Almost surely, 22022102012113 is an apocalyptic number.

It is an amenable number.

2022102012113 is a deficient number, since it is larger than the sum of its proper divisors (6109069855).

2022102012113 is an equidigital number, since it uses as much as digits as its factorization.

2022102012113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6109069854.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 2022102012113 its reverse (3112102012202), we get a palindrome (5134204024315).

The spelling of 2022102012113 in words is "two trillion, twenty-two billion, one hundred two million, twelve thousand, one hundred thirteen".

Divisors: 1 331 6109069523 2022102012113