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2022121030114 = 21011060515057
BaseRepresentation
bin11101011011001111110…
…011100100000111100010
321011022110002110121112201
4131123033303210013202
5231112300440430424
64144541035243414
7266044021105153
oct35331763440742
97138402417481
102022121030114
1170a638672159
12287a982a956a
131188ba4b10c3
146dc2a73792a
1537900066d44
hex1d6cfce41e2

2022121030114 has 4 divisors (see below), whose sum is σ = 3033181545174. Its totient is φ = 1011060515056.

The previous prime is 2022121030067. The next prime is 2022121030183. The reversal of 2022121030114 is 4110301212202.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 1289099098225 + 733021931889 = 1135385^2 + 856167^2 .

It is a junction number, because it is equal to n+sod(n) for n = 2022121030091 and 2022121030100.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505530257527 + ... + 505530257530.

Almost surely, 22022121030114 is an apocalyptic number.

2022121030114 is a deficient number, since it is larger than the sum of its proper divisors (1011060515060).

2022121030114 is a wasteful number, since it uses less digits than its factorization.

2022121030114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1011060515059.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 2022121030114 its reverse (4110301212202), we get a palindrome (6132422242316).

The spelling of 2022121030114 in words is "two trillion, twenty-two billion, one hundred twenty-one million, thirty thousand, one hundred fourteen".

Divisors: 1 2 1011060515057 2022121030114