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2022142011 = 3674047337
BaseRepresentation
bin111100010000111…
…0111000000111011
312012221000110100120
41320201313000323
513120132021021
6532353304323
7101052631521
oct17041670073
95187013316
102022142011
119484a024a
124852650a3
13262c2a746
141527c0311
15bc7d82c6
hex7887703b

2022142011 has 4 divisors (see below), whose sum is σ = 2696189352. Its totient is φ = 1348094672.

The previous prime is 2022142007. The next prime is 2022142097. The reversal of 2022142011 is 1102412202.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2022142011 - 22 = 2022142007 is a prime.

It is a super-2 number, since 2×20221420112 = 8178116625302248242, which contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (2022142411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 337023666 + ... + 337023671.

It is an arithmetic number, because the mean of its divisors is an integer number (674047338).

Almost surely, 22022142011 is an apocalyptic number.

2022142011 is a deficient number, since it is larger than the sum of its proper divisors (674047341).

2022142011 is an equidigital number, since it uses as much as digits as its factorization.

2022142011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 674047340.

The product of its (nonzero) digits is 64, while the sum is 15.

The square root of 2022142011 is about 44968.2333542246. The cubic root of 2022142011 is about 1264.5535272856.

Adding to 2022142011 its reverse (1102412202), we get a palindrome (3124554213).

The spelling of 2022142011 in words is "two billion, twenty-two million, one hundred forty-two thousand, eleven".

Divisors: 1 3 674047337 2022142011