Search a number
-
+
202310013311 = 728901430473
BaseRepresentation
bin1011110001101010011…
…1011101000101111111
3201100012022222112000222
42330122213131011333
511303312330411221
6232535005411555
720421300511460
oct2743247350577
9640168875028
10202310013311
117888780140a
1233261269bbb
1316101a8bc63
149b12bd8d67
1553e11729ab
hex2f1a9dd17f

202310013311 has 4 divisors (see below), whose sum is σ = 231211443792. Its totient is φ = 173408582832.

The previous prime is 202310013281. The next prime is 202310013359. The reversal of 202310013311 is 113310013202.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-202310013311 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 202310013311.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (202310018311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14450715230 + ... + 14450715243.

It is an arithmetic number, because the mean of its divisors is an integer number (57802860948).

Almost surely, 2202310013311 is an apocalyptic number.

202310013311 is a deficient number, since it is larger than the sum of its proper divisors (28901430481).

202310013311 is an equidigital number, since it uses as much as digits as its factorization.

202310013311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28901430480.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 202310013311 its reverse (113310013202), we get a palindrome (315620026513).

The spelling of 202310013311 in words is "two hundred two billion, three hundred ten million, thirteen thousand, three hundred eleven".

Divisors: 1 7 28901430473 202310013311