Search a number
-
+
20231021011 = 31221052051
BaseRepresentation
bin10010110101110111…
…001110000111010011
31221012221020100111111
4102311313032013103
5312413120133021
613143300554151
71314225561355
oct226567160723
957187210444
1020231021011
11864197a583
123b073b2957
131ba5503866
14d9cc610d5
157d61a18e1
hex4b5dce1d3

20231021011 has 6 divisors (see below), whose sum is σ = 20904687636. Its totient is φ = 19578406500.

The previous prime is 20231020993. The next prime is 20231021101. The reversal of 20231021011 is 11012013202.

It is not a de Polignac number, because 20231021011 - 215 = 20230988243 is a prime.

It is a super-2 number, since 2×202310210112 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 20231020982 and 20231021000.

It is not an unprimeable number, because it can be changed into a prime (20231028011) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 10525065 + ... + 10526986.

It is an arithmetic number, because the mean of its divisors is an integer number (3484114606).

Almost surely, 220231021011 is an apocalyptic number.

20231021011 is a deficient number, since it is larger than the sum of its proper divisors (673666625).

20231021011 is an equidigital number, since it uses as much as digits as its factorization.

20231021011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21052113 (or 21052082 counting only the distinct ones).

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 20231021011 its reverse (11012013202), we get a palindrome (31243034213).

The spelling of 20231021011 in words is "twenty billion, two hundred thirty-one million, twenty-one thousand, eleven".

Divisors: 1 31 961 21052051 652613581 20231021011