2023110012115 has 4 divisors (see below), whose sum is σ = 2427732014544. Its totient is φ = 1618488009688.

The previous prime is 2023110012097. The next prime is 2023110012127. The reversal of 2023110012115 is 5112100113202.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2023110012115 - 2⁹ = 2023110011603 is a prime.

It is a super-2 number, since 2×2023110012115² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2023110012092 and 2023110012101.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 202311001207 + ... + 202311001216.

It is an arithmetic number, because the mean of its divisors is an integer number (606933003636).

Almost surely, 2^{2023110012115} is an apocalyptic number.

2023110012115 is a deficient number, since it is larger than the sum of its proper divisors (404622002429).

2023110012115 is an equidigital number, since it uses as much as digits as its factorization.

2023110012115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 404622002428.

The product of its (nonzero) digits is 120, while the sum is 19.

Adding to 2023110012115 its reverse (5112100113202), we get a palindrome (7135210125317).

The spelling of 2023110012115 in words is "two trillion, twenty-three billion, one hundred ten million, twelve thousand, one hundred fifteen".