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2023110012127 is a prime number
BaseRepresentation
bin11101011100001010110…
…000001110110011011111
321011102000000102002211011
4131130022300032303133
5231121312130342002
64145223124440051
7266110360236511
oct35341260166337
97142000362734
102023110012127
1170aaa594aa66
12288113549027
13118a17361269
146dcc1c17bb1
153795bcbd8d7
hex1d70ac0ecdf

2023110012127 has 2 divisors, whose sum is σ = 2023110012128. Its totient is φ = 2023110012126.

The previous prime is 2023110012097. The next prime is 2023110012197. The reversal of 2023110012127 is 7212100113202.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2023110012127 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2023110012098 and 2023110012107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2023110012197) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1011555006063 + 1011555006064.

It is an arithmetic number, because the mean of its divisors is an integer number (1011555006064).

Almost surely, 22023110012127 is an apocalyptic number.

2023110012127 is a deficient number, since it is larger than the sum of its proper divisors (1).

2023110012127 is an equidigital number, since it uses as much as digits as its factorization.

2023110012127 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 336, while the sum is 22.

Adding to 2023110012127 its reverse (7212100113202), we get a palindrome (9235210125329).

The spelling of 2023110012127 in words is "two trillion, twenty-three billion, one hundred ten million, twelve thousand, one hundred twenty-seven".