Base | Representation |
---|---|
bin | 11101011100001011010… |
… | …111000110110101100111 |
3 | 21011102000201120212020000 |
4 | 131130023113012311213 |
5 | 231121322232444421 |
6 | 4145224131112343 |
7 | 266110542663030 |
oct | 35341327066547 |
9 | 7142021525200 |
10 | 2023120203111 |
11 | 710000680667 |
12 | 288116a426b3 |
13 | 118a194bba27 |
14 | 6dcc330ba87 |
15 | 3795cb33226 |
hex | 1d70b5c6d67 |
2023120203111 has 20 divisors (see below), whose sum is σ = 3453933610512. Its totient is φ = 1156068687168.
The previous prime is 2023120203089. The next prime is 2023120203113. The reversal of 2023120203111 is 1113020213202.
2023120203111 is a `hidden beast` number, since 20 + 2 + 312 + 0 + 20 + 311 + 1 = 666.
It is not a de Polignac number, because 2023120203111 - 219 = 2023119678823 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2023120203113) by changing a digit.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 1784056050 + ... + 1784057183.
Almost surely, 22023120203111 is an apocalyptic number.
2023120203111 is a gapful number since it is divisible by the number (21) formed by its first and last digit.
2023120203111 is a deficient number, since it is larger than the sum of its proper divisors (1430813407401).
2023120203111 is an equidigital number, since it uses as much as digits as its factorization.
2023120203111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3568113252 (or 3568113243 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 2023120203111 its reverse (1113020213202), we get a palindrome (3136140416313).
The spelling of 2023120203111 in words is "two trillion, twenty-three billion, one hundred twenty million, two hundred three thousand, one hundred eleven".
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