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2023433120042 = 21011716560021
BaseRepresentation
bin11101011100011110000…
…000110010100100101010
321011102211112101200112222
4131130132000302210222
5231122442334320132
64145315150034042
7266121362511215
oct35343600624452
97142745350488
102023433120042
117101512777a4
122881a37a8922
13118a6928cc89
146dd12ac477c
153797a344412
hex1d71e03292a

2023433120042 has 4 divisors (see below), whose sum is σ = 3035149680066. Its totient is φ = 1011716560020.

The previous prime is 2023433120039. The next prime is 2023433120047. The reversal of 2023433120042 is 2400213343202.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 2014585648321 + 8847471721 = 1419361^2 + 94061^2 .

It is a junction number, because it is equal to n+sod(n) for n = 2023433119993 and 2023433120020.

It is not an unprimeable number, because it can be changed into a prime (2023433120047) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505858280009 + ... + 505858280012.

Almost surely, 22023433120042 is an apocalyptic number.

2023433120042 is a deficient number, since it is larger than the sum of its proper divisors (1011716560024).

2023433120042 is a wasteful number, since it uses less digits than its factorization.

2023433120042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1011716560023.

The product of its (nonzero) digits is 6912, while the sum is 26.

Adding to 2023433120042 its reverse (2400213343202), we get a palindrome (4423646463244).

The spelling of 2023433120042 in words is "two trillion, twenty-three billion, four hundred thirty-three million, one hundred twenty thousand, forty-two".

Divisors: 1 2 1011716560021 2023433120042