Base | Representation |
---|---|
bin | 11101011110000001011… |
… | …001000101011101011001 |
3 | 21011121010201201222021200 |
4 | 131132001121011131121 |
5 | 231134401202330431 |
6 | 4150152430224413 |
7 | 266210606444514 |
oct | 35360131053531 |
9 | 7147121658250 |
10 | 2025100433241 |
11 | 710927444896 |
12 | 28858a055109 |
13 | 118c73833632 |
14 | 700302dbd7b |
15 | 37a268dcee6 |
hex | 1d781645759 |
2025100433241 has 24 divisors (see below), whose sum is σ = 2938247866944. Its totient is φ = 1344020390880.
The previous prime is 2025100433233. The next prime is 2025100433303. The reversal of 2025100433241 is 1423340015202.
2025100433241 is a `hidden beast` number, since 202 + 5 + 1 + 0 + 0 + 433 + 24 + 1 = 666.
It is not a de Polignac number, because 2025100433241 - 23 = 2025100433233 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2025100433201) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 36707620 + ... + 36762746.
It is an arithmetic number, because the mean of its divisors is an integer number (122426994456).
Almost surely, 22025100433241 is an apocalyptic number.
It is an amenable number.
2025100433241 is a deficient number, since it is larger than the sum of its proper divisors (913147433703).
2025100433241 is a wasteful number, since it uses less digits than its factorization.
2025100433241 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 73341 (or 73338 counting only the distinct ones).
The product of its (nonzero) digits is 5760, while the sum is 27.
Adding to 2025100433241 its reverse (1423340015202), we get a palindrome (3448440448443).
The spelling of 2025100433241 in words is "two trillion, twenty-five billion, one hundred million, four hundred thirty-three thousand, two hundred forty-one".
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