Base | Representation |
---|---|
bin | 1001001101011000100111… |
… | …01100011101010011100011 |
3 | 2122200222122001201020112021 |
4 | 10212230103230131103203 |
5 | 10123243223403101430 |
6 | 111023121044442311 |
7 | 4160044111134511 |
oct | 446542354352343 |
9 | 78628561636467 |
10 | 20251101222115 |
11 | 64a8497770805 |
12 | 23309709a9397 |
13 | b3b89456093a |
14 | 5002310094b1 |
15 | 251b9e6c807a |
hex | 126b13b1d4e3 |
20251101222115 has 8 divisors (see below), whose sum is σ = 24302299654080. Its totient is φ = 16200228852672.
The previous prime is 20251101222097. The next prime is 20251101222127. The reversal of 20251101222115 is 51122210115202.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 20251101222115 - 25 = 20251101222083 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 20251101222115.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 81378970 + ... + 81627439.
It is an arithmetic number, because the mean of its divisors is an integer number (3037787456760).
Almost surely, 220251101222115 is an apocalyptic number.
20251101222115 is a deficient number, since it is larger than the sum of its proper divisors (4051198431965).
20251101222115 is a wasteful number, since it uses less digits than its factorization.
20251101222115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 163031261.
The product of its (nonzero) digits is 800, while the sum is 25.
Adding to 20251101222115 its reverse (51122210115202), we get a palindrome (71373311337317).
The spelling of 20251101222115 in words is "twenty trillion, two hundred fifty-one billion, one hundred one million, two hundred twenty-two thousand, one hundred fifteen".
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