Base | Representation |
---|---|
bin | 11101011110001010011… |
… | …111100111100000110111 |
3 | 21011121112101002022022101 |
4 | 131132022133213200313 |
5 | 231140204300444120 |
6 | 4150215523242531 |
7 | 266214442441342 |
oct | 35361237474067 |
9 | 7147471068271 |
10 | 2025253140535 |
11 | 7109a5666069 |
12 | 288611219447 |
13 | 118c9936c891 |
14 | 700466cd459 |
15 | 37a3500490a |
hex | 1d78a7e7837 |
2025253140535 has 16 divisors (see below), whose sum is σ = 2486975531040. Its totient is φ = 1582425976320.
The previous prime is 2025253140517. The next prime is 2025253140541. The reversal of 2025253140535 is 5350413525202.
It is not a de Polignac number, because 2025253140535 - 25 = 2025253140503 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2025253140494 and 2025253140503.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3315195 + ... + 3878275.
It is an arithmetic number, because the mean of its divisors is an integer number (155435970690).
Almost surely, 22025253140535 is an apocalyptic number.
2025253140535 is a deficient number, since it is larger than the sum of its proper divisors (461722390505).
2025253140535 is a wasteful number, since it uses less digits than its factorization.
2025253140535 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 579858.
The product of its (nonzero) digits is 180000, while the sum is 37.
Adding to 2025253140535 its reverse (5350413525202), we get a palindrome (7375666665737).
The spelling of 2025253140535 in words is "two trillion, twenty-five billion, two hundred fifty-three million, one hundred forty thousand, five hundred thirty-five".
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