202540121133133 has 4 divisors (see below), whose sum is σ = 231474424152160. Its totient is φ = 173605818114108.

The previous prime is 202540121133083. The next prime is 202540121133137. The reversal of 202540121133133 is 331331121045202.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 202540121133133 - 2¹⁷ = 202540121002061 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 202540121133095 and 202540121133104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (202540121133137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14467151509503 + ... + 14467151509516.

It is an arithmetic number, because the mean of its divisors is an integer number (57868606038040).

Almost surely, 2^{202540121133133} is an apocalyptic number.

It is an amenable number.

202540121133133 is a deficient number, since it is larger than the sum of its proper divisors (28934303019027).

202540121133133 is an equidigital number, since it uses as much as digits as its factorization.

202540121133133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28934303019026.

The product of its (nonzero) digits is 12960, while the sum is 31.

Adding to 202540121133133 its reverse (331331121045202), we get a palindrome (533871242178335).

The spelling of 202540121133133 in words is "two hundred two trillion, five hundred forty billion, one hundred twenty-one million, one hundred thirty-three thousand, one hundred thirty-three".