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202554404131 = 47139263117889
BaseRepresentation
bin1011110010100100101…
…1101110110100100011
3201100211100211212012211
42330221023232310203
511304312411413011
6233015135502551
720430326012242
oct2745113566443
9640740755184
10202554404131
11789a27538a2
123330b087a57
13161405b9501
149b37454959
155407849b21
hex2f292eed23

202554404131 has 16 divisors (see below), whose sum is σ = 209146291200. Its totient is φ = 196068492288.

The previous prime is 202554404093. The next prime is 202554404189. The reversal of 202554404131 is 131404455202.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-202554404131 is a prime.

It is a super-2 number, since 2×2025544041312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 202554404093 and 202554404102.

It is not an unprimeable number, because it can be changed into a prime (202554404191) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1659235 + ... + 1777123.

It is an arithmetic number, because the mean of its divisors is an integer number (13071643200).

Almost surely, 2202554404131 is an apocalyptic number.

202554404131 is a deficient number, since it is larger than the sum of its proper divisors (6591887069).

202554404131 is a wasteful number, since it uses less digits than its factorization.

202554404131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 118338.

The product of its (nonzero) digits is 19200, while the sum is 31.

Adding to 202554404131 its reverse (131404455202), we get a palindrome (333958859333).

The spelling of 202554404131 in words is "two hundred two billion, five hundred fifty-four million, four hundred four thousand, one hundred thirty-one".

Divisors: 1 47 139 263 6533 12361 36557 117889 1718179 5540783 16386571 31004807 770168837 1457225929 4309668173 202554404131