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2030040234115 = 51213953935089
BaseRepresentation
bin11101100010100111110…
…100111011100010000011
321012001212222211212011121
4131202213310323202003
5231230010244442430
64152330531253111
7266444201165365
oct35424764734203
97161788755147
102030040234115
11712a31875353
1228952844a197
1311958007572a
147037c3acd35
1537c15402a7a
hex1d8a7d3b883

2030040234115 has 16 divisors (see below), whose sum is σ = 2438381642400. Its totient is φ = 1622476979712.

The previous prime is 2030040234109. The next prime is 2030040234121. The reversal of 2030040234115 is 5114320400302.

It is an interprime number because it is at equal distance from previous prime (2030040234109) and next prime (2030040234121).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2030040234115 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2030040234115.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 57836491 + ... + 57871579.

It is an arithmetic number, because the mean of its divisors is an integer number (152398852650).

Almost surely, 22030040234115 is an apocalyptic number.

2030040234115 is a deficient number, since it is larger than the sum of its proper divisors (408341408285).

2030040234115 is a wasteful number, since it uses less digits than its factorization.

2030040234115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 45846.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 2030040234115 its reverse (5114320400302), we get a palindrome (7144360634417).

The spelling of 2030040234115 in words is "two trillion, thirty billion, forty million, two hundred thirty-four thousand, one hundred fifteen".

Divisors: 1 5 1213 6065 9539 35089 47695 175445 11570807 42562957 57854035 212814785 334713971 1673569855 406008046823 2030040234115