Base | Representation |
---|---|
bin | 10010111010000011… |
… | …011110110100010001 |
3 | 1221101211120010112021 |
4 | 102322003132310101 |
5 | 313034121002032 |
6 | 13154252131441 |
7 | 1316041401613 |
oct | 227203366421 |
9 | 57354503467 |
10 | 20301344017 |
11 | 8678641269 |
12 | 3b26a66b81 |
13 | 1bb6c563c6 |
14 | da8328db3 |
15 | 7dc443097 |
hex | 4ba0ded11 |
20301344017 has 4 divisors (see below), whose sum is σ = 20322339136. Its totient is φ = 20280348900.
The previous prime is 20301344003. The next prime is 20301344057. The reversal of 20301344017 is 71044310302.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 20301344017 - 215 = 20301311249 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 20301343982 and 20301344000.
It is not an unprimeable number, because it can be changed into a prime (20301344057) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10496109 + ... + 10498042.
It is an arithmetic number, because the mean of its divisors is an integer number (5080584784).
Almost surely, 220301344017 is an apocalyptic number.
It is an amenable number.
20301344017 is a deficient number, since it is larger than the sum of its proper divisors (20995119).
20301344017 is an equidigital number, since it uses as much as digits as its factorization.
20301344017 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 20995118.
The product of its (nonzero) digits is 2016, while the sum is 25.
Adding to 20301344017 its reverse (71044310302), we get a palindrome (91345654319).
The spelling of 20301344017 in words is "twenty billion, three hundred one million, three hundred forty-four thousand, seventeen".
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