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2030404043131 = 17231178412097
BaseRepresentation
bin11101100010111101100…
…000110000000101111011
321012002211100102021022121
4131202331200300011323
5231231231413340011
64152431005102111
7266456206415152
oct35427540600573
97162740367277
102030404043131
117130a9171462
1228960a257937
1311960a555139
14703b4832599
1537c37317e71
hex1d8bd83017b

2030404043131 has 4 divisors (see below), whose sum is σ = 2031582456952. Its totient is φ = 2029225629312.

The previous prime is 2030404043123. The next prime is 2030404043137. The reversal of 2030404043131 is 1313404040302.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2030404043131 - 23 = 2030404043123 is a prime.

It is a super-2 number, since 2×20304040431312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2030404043096 and 2030404043105.

It is not an unprimeable number, because it can be changed into a prime (2030404043137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 589204326 + ... + 589207771.

It is an arithmetic number, because the mean of its divisors is an integer number (507895614238).

Almost surely, 22030404043131 is an apocalyptic number.

2030404043131 is a deficient number, since it is larger than the sum of its proper divisors (1178413821).

2030404043131 is a wasteful number, since it uses less digits than its factorization.

2030404043131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1178413820.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 2030404043131 its reverse (1313404040302), we get a palindrome (3343808083433).

The spelling of 2030404043131 in words is "two trillion, thirty billion, four hundred four million, forty-three thousand, one hundred thirty-one".

Divisors: 1 1723 1178412097 2030404043131