Search a number
-
+
203102112021 = 367700704007
BaseRepresentation
bin1011110100100111010…
…1000100100100010101
3201102020112110022012020
42331021311010210111
511311423120041041
6233145343043353
720450026316244
oct2751165044425
9642215408166
10203102112021
1179153935946
12334425a0559
13161c9c06613
149b8a0a895b
15543a988866
hex2f49d44915

203102112021 has 4 divisors (see below), whose sum is σ = 270802816032. Its totient is φ = 135401408012.

The previous prime is 203102111983. The next prime is 203102112041. The reversal of 203102112021 is 120211201302.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 203102112021 - 27 = 203102111893 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (203102112041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33850352001 + ... + 33850352006.

It is an arithmetic number, because the mean of its divisors is an integer number (67700704008).

Almost surely, 2203102112021 is an apocalyptic number.

It is an amenable number.

203102112021 is a deficient number, since it is larger than the sum of its proper divisors (67700704011).

203102112021 is an equidigital number, since it uses as much as digits as its factorization.

203102112021 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 67700704010.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 203102112021 its reverse (120211201302), we get a palindrome (323313313323).

The spelling of 203102112021 in words is "two hundred three billion, one hundred two million, one hundred twelve thousand, twenty-one".

Divisors: 1 3 67700704007 203102112021