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203201314441 = 316554881111
BaseRepresentation
bin1011110100111110111…
…1011111111010001001
3201102111110010022022221
42331033233133322021
511312124014030231
6233203245214041
720452342450156
oct2751757377211
9642443108287
10203201314441
11791a4932114
123346b861321
131621462b088
149b9932d22d
155444531d11
hex2f4fbdfe89

203201314441 has 4 divisors (see below), whose sum is σ = 209756195584. Its totient is φ = 196646433300.

The previous prime is 203201314397. The next prime is 203201314447. The reversal of 203201314441 is 144413102302.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 203201314441 - 29 = 203201313929 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (203201314447) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3277440525 + ... + 3277440586.

It is an arithmetic number, because the mean of its divisors is an integer number (52439048896).

Almost surely, 2203201314441 is an apocalyptic number.

It is an amenable number.

203201314441 is a deficient number, since it is larger than the sum of its proper divisors (6554881143).

203201314441 is an equidigital number, since it uses as much as digits as its factorization.

203201314441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6554881142.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 203201314441 its reverse (144413102302), we get a palindrome (347614416743).

The spelling of 203201314441 in words is "two hundred three billion, two hundred one million, three hundred fourteen thousand, four hundred forty-one".

Divisors: 1 31 6554881111 203201314441