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2034411101207 = 4968974094231
BaseRepresentation
bin11101100110101100010…
…110011101110000010111
321012111011121101220121222
4131212230112131300113
5231312433220214312
64154332350200555
7266660414016212
oct35465426356027
97174147356558
102034411101207
11714875036501
1228a3481b315b
13119ac8778314
1470674aa2779
1537dbded4672
hex1d9ac59dc17

2034411101207 has 4 divisors (see below), whose sum is σ = 2034415692336. Its totient is φ = 2034406510080.

The previous prime is 2034411101111. The next prime is 2034411101221. The reversal of 2034411101207 is 7021011144302.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2034411101207 - 232 = 2030116133911 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2034411101227) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1550219 + ... + 2544012.

It is an arithmetic number, because the mean of its divisors is an integer number (508603923084).

Almost surely, 22034411101207 is an apocalyptic number.

2034411101207 is a deficient number, since it is larger than the sum of its proper divisors (4591129).

2034411101207 is an equidigital number, since it uses as much as digits as its factorization.

2034411101207 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4591128.

The product of its (nonzero) digits is 1344, while the sum is 26.

Adding to 2034411101207 its reverse (7021011144302), we get a palindrome (9055422245509).

The spelling of 2034411101207 in words is "two trillion, thirty-four billion, four hundred eleven million, one hundred one thousand, two hundred seven".

Divisors: 1 496897 4094231 2034411101207