2040121313 has 4 divisors (see below), whose sum is σ = 2068855488. Its totient is φ = 2011387140.

The previous prime is 2040121301. The next prime is 2040121351. The reversal of 2040121313 is 3131210402.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3131210402 = 2 ⋅1565605201.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2040121313 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2040121291 and 2040121300.

It is not an unprimeable number, because it can be changed into a prime (2040121513) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14366981 + ... + 14367122.

It is an arithmetic number, because the mean of its divisors is an integer number (517213872).

Almost surely, 2^2040121313 is an apocalyptic number.

It is an amenable number.

2040121313 is a deficient number, since it is larger than the sum of its proper divisors (28734175).

2040121313 is an equidigital number, since it uses as much as digits as its factorization.

2040121313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28734174.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 2040121313 is about 45167.7021000626. The cubic root of 2040121313 is about 1268.2902806194.

Adding to 2040121313 its reverse (3131210402), we get a palindrome (5171331715).

It can be divided in two parts, 20401 and 21313, that added together give a palindrome (41714).

The spelling of 2040121313 in words is "two billion, forty million, one hundred twenty-one thousand, three hundred thirteen".