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204013220441213 = 1447371409544349
BaseRepresentation
bin101110011000110010000111…
…100010001010110001111101
3222202100110210002220202110102
4232120302013202022301331
5203220023033413104323
62001522213555250445
760654316534240211
oct5630620742126175
9882313702822412
10204013220441213
115a006580364097
121aa6b1668a9a25
1389ab49701c7a1
143854414ab2941
15188bcba9e2328
hexb98c8788ac7d

204013220441213 has 4 divisors (see below), whose sum is σ = 204014630130300. Its totient is φ = 204011810752128.

The previous prime is 204013220441201. The next prime is 204013220441237. The reversal of 204013220441213 is 312144022310402.

204013220441213 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 111928507459129 + 92084712982084 = 10579627^2 + 9596078^2 .

It is a cyclic number.

It is not a de Polignac number, because 204013220441213 - 210 = 204013220440189 is a prime.

It is a super-2 number, since 2×2040132204412132 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (204013220441273) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 704627438 + ... + 704916911.

It is an arithmetic number, because the mean of its divisors is an integer number (51003657532575).

Almost surely, 2204013220441213 is an apocalyptic number.

It is an amenable number.

204013220441213 is a deficient number, since it is larger than the sum of its proper divisors (1409689087).

204013220441213 is a wasteful number, since it uses less digits than its factorization.

204013220441213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1409689086.

The product of its (nonzero) digits is 9216, while the sum is 29.

Adding to 204013220441213 its reverse (312144022310402), we get a palindrome (516157242751615).

The spelling of 204013220441213 in words is "two hundred four trillion, thirteen billion, two hundred twenty million, four hundred forty-one thousand, two hundred thirteen".

Divisors: 1 144737 1409544349 204013220441213