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2040134100231 = 331116671311721
BaseRepresentation
bin11101101100000001011…
…101111110010100000111
321020000221110020101101210
4131230001131332110013
5231411143312201411
64201120310022503
7300252265504443
oct35540135762407
97200843211353
102040134100231
11717241571367
1228b484947a33
1311a4cb339786
1470a58ba7823
1538106652ca6
hex1db0177e507

2040134100231 has 16 divisors (see below), whose sum is σ = 2730564465408. Its totient is φ = 1354901822400.

The previous prime is 2040134100229. The next prime is 2040134100239. The reversal of 2040134100231 is 1320014310402.

It is not a de Polignac number, because 2040134100231 - 21 = 2040134100229 is a prime.

It is a super-2 number, since 2×20401341002312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2040134100198 and 2040134100207.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2040134100239) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 899451 + ... + 2211171.

It is an arithmetic number, because the mean of its divisors is an integer number (170660279088).

Almost surely, 22040134100231 is an apocalyptic number.

2040134100231 is a deficient number, since it is larger than the sum of its proper divisors (690430365177).

2040134100231 is a wasteful number, since it uses less digits than its factorization.

2040134100231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1313702.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 2040134100231 its reverse (1320014310402), we get a palindrome (3360148410633).

The spelling of 2040134100231 in words is "two trillion, forty billion, one hundred thirty-four million, one hundred thousand, two hundred thirty-one".

Divisors: 1 3 311 933 1667 5001 518437 1311721 1555311 3935163 407945231 1223835693 2186638907 6559916721 680044700077 2040134100231