Base | Representation |
---|---|
bin | 11101101100000111010… |
… | …111101011101000000001 |
3 | 21020001012100112210220121 |
4 | 131230013113223220001 |
5 | 231411344134122423 |
6 | 4201134204140241 |
7 | 300254610221605 |
oct | 35540727535001 |
9 | 7201170483817 |
10 | 2040233114113 |
11 | 717292449a17 |
12 | 28b4b1b37681 |
13 | 11a5159c647c |
14 | 70a67dbd505 |
15 | 381101b045d |
hex | 1db075eba01 |
2040233114113 has 4 divisors (see below), whose sum is σ = 2106047085568. Its totient is φ = 1974419142660.
The previous prime is 2040233114099. The next prime is 2040233114137. The reversal of 2040233114113 is 3114113320402.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2040233114113 - 233 = 2031643179521 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2040233114713) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32906985681 + ... + 32906985742.
It is an arithmetic number, because the mean of its divisors is an integer number (526511771392).
Almost surely, 22040233114113 is an apocalyptic number.
It is an amenable number.
2040233114113 is a deficient number, since it is larger than the sum of its proper divisors (65813971455).
2040233114113 is an equidigital number, since it uses as much as digits as its factorization.
2040233114113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65813971454.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 2040233114113 its reverse (3114113320402), we get a palindrome (5154346434515).
The spelling of 2040233114113 in words is "two trillion, forty billion, two hundred thirty-three million, one hundred fourteen thousand, one hundred thirteen".
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