Base | Representation |
---|---|
bin | 11101101100001011100… |
… | …011001100100011000011 |
3 | 21020001101020111122110221 |
4 | 131230023203030203003 |
5 | 231412020112211121 |
6 | 4201145151203511 |
7 | 300256421255431 |
oct | 35541343144303 |
9 | 7201336448427 |
10 | 2040303241411 |
11 | 717318a97666 |
12 | 28b511516597 |
13 | 11a5273aac06 |
14 | 70a73435d51 |
15 | 38116413b41 |
hex | 1db0b8cc8c3 |
2040303241411 has 4 divisors (see below), whose sum is σ = 2066129864800. Its totient is φ = 2014476618024.
The previous prime is 2040303241373. The next prime is 2040303241439. The reversal of 2040303241411 is 1141423030402.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2040303241411 - 27 = 2040303241283 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2040303241111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12913311576 + ... + 12913311733.
It is an arithmetic number, because the mean of its divisors is an integer number (516532466200).
Almost surely, 22040303241411 is an apocalyptic number.
2040303241411 is a deficient number, since it is larger than the sum of its proper divisors (25826623389).
2040303241411 is an equidigital number, since it uses as much as digits as its factorization.
2040303241411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25826623388.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 2040303241411 its reverse (1141423030402), we get a palindrome (3181726271813).
The spelling of 2040303241411 in words is "two trillion, forty billion, three hundred three million, two hundred forty-one thousand, four hundred eleven".
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