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204031113 = 31113475597
BaseRepresentation
bin11000010100101…
…00010010001001
3112012220212001220
430022110102021
5404212443423
632125032253
75025143616
oct1412242211
9465825056
10204031113
11a5196660
12583b5689
1333369090
141d15150d
1512da39e3
hexc294489

204031113 has 16 divisors (see below), whose sum is σ = 319601856. Its totient is φ = 114143040.

The previous prime is 204031109. The next prime is 204031133. The reversal of 204031113 is 311130402.

It is not a de Polignac number, because 204031113 - 22 = 204031109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 204031092 and 204031101.

It is not an unprimeable number, because it can be changed into a prime (204031103) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 237370 + ... + 238227.

It is an arithmetic number, because the mean of its divisors is an integer number (19975116).

Almost surely, 2204031113 is an apocalyptic number.

It is an amenable number.

204031113 is a deficient number, since it is larger than the sum of its proper divisors (115570743).

204031113 is a wasteful number, since it uses less digits than its factorization.

204031113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 475624.

The product of its (nonzero) digits is 72, while the sum is 15.

The square root of 204031113 is about 14283.9459884165. The cubic root of 204031113 is about 588.7064574430.

Adding to 204031113 its reverse (311130402), we get a palindrome (515161515).

It can be divided in two parts, 2040 and 31113, that added together give a triangular number (33153 = T257).

The spelling of 204031113 in words is "two hundred four million, thirty-one thousand, one hundred thirteen".

Divisors: 1 3 11 13 33 39 143 429 475597 1426791 5231567 6182761 15694701 18548283 68010371 204031113