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20403142113121 = 59345815968019
BaseRepresentation
bin1001010001110011110100…
…00010011011011101100001
32200020112002001110202112121
410220321322002123131201
510133241113340104441
6111221024000424241
74204035611316355
oct450717202333541
980215061422477
1020403142113121
116556a188a5539
122356323018081
13b500148a36c1
1450773585b465
15255aec545dd1
hex128e7a09b761

20403142113121 has 4 divisors (see below), whose sum is σ = 20748958081200. Its totient is φ = 20057326145044.

The previous prime is 20403142113113. The next prime is 20403142113131. The reversal of 20403142113121 is 12131124130402.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20403142113121 - 23 = 20403142113113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20403142113131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 172907983951 + ... + 172907984068.

It is an arithmetic number, because the mean of its divisors is an integer number (5187239520300).

Almost surely, 220403142113121 is an apocalyptic number.

It is an amenable number.

20403142113121 is a deficient number, since it is larger than the sum of its proper divisors (345815968079).

20403142113121 is an equidigital number, since it uses as much as digits as its factorization.

20403142113121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 345815968078.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 20403142113121 its reverse (12131124130402), we get a palindrome (32534266243523).

The spelling of 20403142113121 in words is "twenty trillion, four hundred three billion, one hundred forty-two million, one hundred thirteen thousand, one hundred twenty-one".

Divisors: 1 59 345815968019 20403142113121