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204101113 = 1511351663
BaseRepresentation
bin11000010101001…
…01010111111001
3112020001102002111
430022211113321
5404222213423
632130332321
75025554656
oct1412452771
9466042074
10204101113
11a5234207
125842a0a1
1333391bb8
141d16cc2d
1512db960d
hexc2a55f9

204101113 has 4 divisors (see below), whose sum is σ = 205452928. Its totient is φ = 202749300.

The previous prime is 204101111. The next prime is 204101123. The reversal of 204101113 is 311101402.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 204101113 - 21 = 204101111 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 204101093 and 204101102.

It is not an unprimeable number, because it can be changed into a prime (204101111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 675681 + ... + 675982.

It is an arithmetic number, because the mean of its divisors is an integer number (51363232).

Almost surely, 2204101113 is an apocalyptic number.

It is an amenable number.

204101113 is a deficient number, since it is larger than the sum of its proper divisors (1351815).

204101113 is a wasteful number, since it uses less digits than its factorization.

204101113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1351814.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 204101113 is about 14286.3960815875. The cubic root of 204101113 is about 588.7737751829.

Adding to 204101113 its reverse (311101402), we get a palindrome (515202515).

The spelling of 204101113 in words is "two hundred four million, one hundred one thousand, one hundred thirteen".

Divisors: 1 151 1351663 204101113