Base | Representation |
---|---|
bin | 1001010010000100011000… |
… | …11110010101011110011001 |
3 | 2200021101001020221222210210 |
4 | 10221002030132111132121 |
5 | 10133412330041244423 |
6 | 111225055022201333 |
7 | 4204502261521434 |
oct | 451021436253631 |
9 | 80241036858723 |
10 | 20412041353113 |
11 | 655a775226233 |
12 | 2357ba7423249 |
13 | b50b02505297 |
14 | 507d3b72481b |
15 | 255e6d96cb93 |
hex | 12908c795799 |
20412041353113 has 16 divisors (see below), whose sum is σ = 30069912583296. Its totient is φ = 12250705125120.
The previous prime is 20412041353111. The next prime is 20412041353127. The reversal of 20412041353113 is 31135314021402.
It is not a de Polignac number, because 20412041353113 - 21 = 20412041353111 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (20412041353111) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8700783718 + ... + 8700786063.
It is an arithmetic number, because the mean of its divisors is an integer number (1879369536456).
Almost surely, 220412041353113 is an apocalyptic number.
20412041353113 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
It is an amenable number.
20412041353113 is a deficient number, since it is larger than the sum of its proper divisors (9657871230183).
20412041353113 is a wasteful number, since it uses less digits than its factorization.
20412041353113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17401569824.
The product of its (nonzero) digits is 8640, while the sum is 30.
Adding to 20412041353113 its reverse (31135314021402), we get a palindrome (51547355374515).
The spelling of 20412041353113 in words is "twenty trillion, four hundred twelve billion, forty-one million, three hundred fifty-three thousand, one hundred thirteen".
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