Base | Representation |
---|---|
bin | 1001010010111110110100… |
… | …10001000000010011011111 |
3 | 2200101101000110221222210021 |
4 | 10221133122101000103133 |
5 | 10134421101240034242 |
6 | 111251323512053011 |
7 | 4206662534335051 |
oct | 451373221002337 |
9 | 80341013858707 |
10 | 20443411252447 |
11 | 6572002769977 |
12 | 23620a1094167 |
13 | b53a6163a0b1 |
14 | 509675a878d1 |
15 | 256ba7992b67 |
hex | 1297da4404df |
20443411252447 has 4 divisors (see below), whose sum is σ = 20443444985160. Its totient is φ = 20443377519736.
The previous prime is 20443411252367. The next prime is 20443411252519. The reversal of 20443411252447 is 74425211434402.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 20443411252447 - 231 = 20441263768799 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20443411250447) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15940348 + ... + 17175025.
It is an arithmetic number, because the mean of its divisors is an integer number (5110861246290).
Almost surely, 220443411252447 is an apocalyptic number.
20443411252447 is a deficient number, since it is larger than the sum of its proper divisors (33732713).
20443411252447 is an equidigital number, since it uses as much as digits as its factorization.
20443411252447 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 33732712.
The product of its (nonzero) digits is 860160, while the sum is 43.
Adding to 20443411252447 its reverse (74425211434402), we get a palindrome (94868622686849).
The spelling of 20443411252447 in words is "twenty trillion, four hundred forty-three billion, four hundred eleven million, two hundred fifty-two thousand, four hundred forty-seven".
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