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2054230514335 = 51121336640159
BaseRepresentation
bin11101111001001001101…
…011100001101010011111
321021101022212010102021001
4131321021223201222133
5232124031002424320
64211411145051131
7301261514161606
oct35711153415237
97241285112231
102054230514335
1172221563197a
12292159786aa7
1311b936904bcc
14715d4dbaa3d
153867de7d20a
hex1de49ae1a9f

2054230514335 has 8 divisors (see below), whose sum is σ = 2465296525440. Its totient is φ = 1643237805984.

The previous prime is 2054230514327. The next prime is 2054230514389. The reversal of 2054230514335 is 5334150324502.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2054230514335 - 23 = 2054230514327 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2054230514294 and 2054230514303.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 18264015 + ... + 18376144.

It is an arithmetic number, because the mean of its divisors is an integer number (308162065680).

Almost surely, 22054230514335 is an apocalyptic number.

2054230514335 is a deficient number, since it is larger than the sum of its proper divisors (411066011105).

2054230514335 is a wasteful number, since it uses less digits than its factorization.

2054230514335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 36651377.

The product of its (nonzero) digits is 216000, while the sum is 37.

Adding to 2054230514335 its reverse (5334150324502), we get a palindrome (7388380838837).

The spelling of 2054230514335 in words is "two trillion, fifty-four billion, two hundred thirty million, five hundred fourteen thousand, three hundred thirty-five".

Divisors: 1 5 11213 56065 36640159 183200795 410846102867 2054230514335