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206475210141 = 368825070047
BaseRepresentation
bin1100000001001011100…
…0011010110110011101
3201201221121112102221020
43000102320122312131
511340330123211031
6234504200154353
720626435220454
oct3002270326635
9651847472836
10206475210141
117a624967442
12340241689b9
13166169a0675
149dca071b9b
155586b7a096
hex3012e1ad9d

206475210141 has 4 divisors (see below), whose sum is σ = 275300280192. Its totient is φ = 137650140092.

The previous prime is 206475210113. The next prime is 206475210197. The reversal of 206475210141 is 141012574602.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 206475210141 - 210 = 206475209117 is a prime.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (206475250141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34412535021 + ... + 34412535026.

It is an arithmetic number, because the mean of its divisors is an integer number (68825070048).

Almost surely, 2206475210141 is an apocalyptic number.

It is an amenable number.

206475210141 is a deficient number, since it is larger than the sum of its proper divisors (68825070051).

206475210141 is an equidigital number, since it uses as much as digits as its factorization.

206475210141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 68825070050.

The product of its (nonzero) digits is 13440, while the sum is 33.

Adding to 206475210141 its reverse (141012574602), we get a palindrome (347487784743).

The spelling of 206475210141 in words is "two hundred six billion, four hundred seventy-five million, two hundred ten thousand, one hundred forty-one".

Divisors: 1 3 68825070047 206475210141