Base | Representation |
---|---|
bin | 11110000011100000011… |
… | …101011110001001010101 |
3 | 21022110000210122010021101 |
4 | 132003200131132021111 |
5 | 232314314112432432 |
6 | 4220450404550101 |
7 | 302134205252200 |
oct | 36034035361125 |
9 | 7273023563241 |
10 | 2065350124117 |
11 | 726a01335325 |
12 | 2943416b2331 |
13 | 11c9b954a977 |
14 | 71d6bb04937 |
15 | 38ad02974e7 |
hex | 1e0e075e255 |
2065350124117 has 12 divisors (see below), whose sum is σ = 2408889348480. Its totient is φ = 1765629113976.
The previous prime is 2065350124043. The next prime is 2065350124133. The reversal of 2065350124117 is 7114210535602.
It is not a de Polignac number, because 2065350124117 - 215 = 2065350091349 is a prime.
It is a super-2 number, since 2×20653501241172 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2065350124217) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 55588293 + ... + 55625434.
It is an arithmetic number, because the mean of its divisors is an integer number (200740779040).
Almost surely, 22065350124117 is an apocalyptic number.
It is an amenable number.
2065350124117 is a deficient number, since it is larger than the sum of its proper divisors (343539224363).
2065350124117 is a wasteful number, since it uses less digits than its factorization.
2065350124117 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 111214120 (or 111214113 counting only the distinct ones).
The product of its (nonzero) digits is 50400, while the sum is 37.
Adding to 2065350124117 its reverse (7114210535602), we get a palindrome (9179560659719).
The spelling of 2065350124117 in words is "two trillion, sixty-five billion, three hundred fifty million, one hundred twenty-four thousand, one hundred seventeen".
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