Base | Representation |
---|---|
bin | 11110100011110001110… |
… | …100100001111011110001 |
3 | 21102202110200121002112201 |
4 | 132203301310201323301 |
5 | 233401300241314420 |
6 | 4244421024023201 |
7 | 304501661666566 |
oct | 36436164417361 |
9 | 7382420532481 |
10 | 2100001119985 |
11 | 73a67298139a |
12 | 29abb2161b01 |
13 | 12304c376812 |
14 | 738d7b2286d |
15 | 3995c38910a |
hex | 1e8f1d21ef1 |
2100001119985 has 16 divisors (see below), whose sum is σ = 2523413612880. Its totient is φ = 1677726545920.
The previous prime is 2100001119961. The next prime is 2100001119991. The reversal of 2100001119985 is 5899111000012.
It can be written as a sum of positive squares in 8 ways, for example, as 47933409969 + 2052067710016 = 218937^2 + 1432504^2 .
It is not a de Polignac number, because 2100001119985 - 217 = 2100000988913 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 41156649 + ... + 41207641.
It is an arithmetic number, because the mean of its divisors is an integer number (157713350805).
Almost surely, 22100001119985 is an apocalyptic number.
It is an amenable number.
2100001119985 is a deficient number, since it is larger than the sum of its proper divisors (423412492895).
2100001119985 is a wasteful number, since it uses less digits than its factorization.
2100001119985 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 61988.
The product of its (nonzero) digits is 6480, while the sum is 37.
Adding to 2100001119985 its reverse (5899111000012), we get a palindrome (7999112119997).
The spelling of 2100001119985 in words is "two trillion, one hundred billion, one million, one hundred nineteen thousand, nine hundred eighty-five".
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